JEE Main & Advanced Sample Paper JEE Main - Mock Test - 41

  • question_answer
    Solubility of calcium phosphate (molecular mass, M) in water is W g per 100 mL at \[25{}^\circ C\]. Its solubility product at \[25{}^\circ C\] will be approximately-

    A) \[{{10}^{9}}{{\left( \frac{W}{M} \right)}^{5}}\]         

    B)        \[{{10}^{7}}{{\left( \frac{W}{M} \right)}^{5}}\]

    C) \[{{10}^{5}}{{\left( \frac{W}{M} \right)}^{5}}\]         

    D)        \[{{10}^{3}}{{\left( \frac{W}{M} \right)}^{5}}\]

    Correct Answer: C

    Solution :

    [b] Solubility \[S=\frac{10\,W}{M}\frac{mol}{lit}\] \[{{K}_{sp}}\text{ }of\,C{{a}_{3}}{{\left( P{{O}_{4}} \right)}_{2}}=108\text{ }{{S}^{5}}\] \[=108\times {{10}^{5}}{{\left( \frac{W}{M} \right)}^{5}}\]


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