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JEE Main & Advanced Sample Paper JEE Main - Mock Test - 42

  • question_answer
    Let a die is loaded in such a way that prime number faces are twice as likely to occur as a nonprime number faces. The probability that an odd number will be show up when die is tossed is-

    A) \[\frac{1}{3}\]              

    B)        \[\frac{2}{3}\]

    C) \[\frac{4}{9}\]              

    D)        \[\frac{5}{9}\]

    Correct Answer: D

    Solution :

    [d] Let    \[P\left( 2 \right)=P\left( 3 \right)=P\left( 5 \right)=2x\] \[P\left( 1 \right)=P\left( 4 \right)=P\left( 6 \right)=x\] Now \[P\left( 1 \right)+P\left( 2 \right)+P\left( 3 \right)+P\left( 4 \right)+P\left( 5 \right)+P\left( 6 \right)=1\] \[x=\frac{1}{9}\] P(odd number) \[=x+2x+2x\]                         \[=\text{ }5x\]                         \[=\frac{5}{9}\]


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