A) \[2\times {{10}^{-15}}J\]
B) \[4\times {{10}^{-14}}J\]
C) \[2.5\times {{10}^{-13}}J\]
D) \[8\times {{10}^{-6}}J\]
Correct Answer: C
Solution :
[c] Required energy \[=931.5\times {{10}^{6}}\times 1.6\times {{10}^{-19}}\] \[\left[ {{m}_{Be}}+{{m}_{n}}-{{m}_{p}}-{{m}_{Li}} \right]=2.5\times {{10}^{-13}}Joule\]
You need to login to perform this action.
You will be redirected in
3 sec
