| Column I (Compound) | Column II (CFSE (Crystal Field Splitting Energy)) |
| I. \[{{[Cr{{({{H}_{2}}O)}_{6}}]}^{2+}}\] (When \[\Delta <p\]) | P. \[-0.6\,{{\Delta }_{o}}\] |
| II. \[{{[FeC{{l}_{4}}]}^{\Theta }}\] (When \[\Delta <p\]) | Q. \[1-6\,{{\Delta }_{o}}+P\] |
| III. \[{{[Fe{{O}_{4}}]}^{2-}}\] (When \[\Delta <p\]) | R. Zero |
| IV. \[{{[Cr{{(N{{H}_{3}})}_{6}}]}^{2+}}\](When\[\Delta >P\]) | S. \[-1.2\,{{\Delta }_{t}}\] |
A) I - Q II - S III - R IV - P
B) I - R II - S III - Q IV - Q
C) I - P II - R III - S IV - Q
D) I - S II - Q III - P IV - R
Correct Answer: C
Solution :
[c] (I) Octahedral complex, \[C.N.=6,\]\[{{\Delta }_{0}}<P\] (Weak ligand, no pairing, high spin state) \[Cr=3{{d}^{5}}\,4{{s}^{1}},\,C{{r}^{+2}}=3{{d}^{4}}\]Structure \[=(t_{2g}^{3}\,e_{g}^{1})\] CFSE \[=(-0.4\times 3+0.6){{\Delta }_{0}}=-0.6{{\Delta }_{0}}\] (II) Tetrahedral complex, \[C.N.=4\] (\[{{\Delta }_{t}}<P\] weak ligand, no pairing, high spin). \[Fe=3{{d}^{6}}4{{s}^{2}},F{{e}^{+3}}=3{{d}^{5}}\] Structure is \[\left( {{e}^{2}}{{t}^{3}}_{2} \right)\] CFSE \[=-0.6\times 2+0.4\times 3=0\] (III) Tetrahedral complex, \[C.N.=4,\,{{\Delta }_{t}}<P\] weak ligand, no pairing high spin \[Fe=3{{d}^{6}}4{{s}^{2}},\] \[F{{e}^{+6}}=3{{d}^{2}}\Rightarrow ({{e}^{2}}{{t}_{2}}^{0})\] CFSE \[=(-0.6\times 2){{\Delta }_{t}}=1.2{{\Delta }_{t}}\] (IV) Octahedral complex, \[C.N.=6,\,{{\Delta }_{0}}<P\] (Strong ligand, no pairing, high spin state) \[Cr=3{{d}^{5}}4{{s}^{1}},C{{r}^{+2}}=3{{d}^{4}}\] Structure \[=(t_{2g}^{4}\,e_{g}^{0})\] CFSE \[=(-0.4\times 4){{\Delta }_{0}}+P=-1.6+{{\Delta }_{0}}+P\]
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