A) \[2\times {{10}^{9}}\,newton/metr{{e}^{2}}\]
B) \[2\times {{10}^{8}}\,newton/metr{{e}^{2}}\]
C) \[2\times {{10}^{6}}\,newton/metr{{e}^{2}}\]
D) \[2\times {{10}^{4}}\,newton/metr{{e}^{2}}\]
Correct Answer: C
Solution :
[c] \[B=\frac{-Vdp}{dV}\] \[\therefore dp=\frac{-BdV}{V}\] \[\therefore dp=B\frac{d\rho }{\rho }\] \[=2\times {{10}^{9}}\times {{10}^{-3}}=2\times {{10}^{6}}Pa\]
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