JEE Main & Advanced Sample Paper JEE Main - Mock Test - 44

  • question_answer
    A 50 Hz ac source of 20 volts is connected across R and C as shown in figure. The voltage across R is 12 volt. The voltage across C is -

    A) 8 V

    B) 16 V

    C) 10 V

    D) Not possible to determine unless values of R and C are given

    Correct Answer: B

    Solution :

    [b] \[{{V}_{source}}=\sqrt{V_{R}^{2}+V_{C}^{2}}\] \[\therefore {{V}_{C}}=\sqrt{V_{source}^{2}-V_{R}^{2}}\] \[=\sqrt{{{(20)}^{2}}-{{(12)}^{2}}}=16V\]


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