A) \[{{10}^{-2}}\]
B) \[{{10}^{-3}}\]
C) \[{{10}^{-4}}\]
D) \[{{10}^{-5}}\]
Correct Answer: B
Solution :
[b]: Degree of hydrolysis, \[h=\sqrt{\frac{{{K}_{w}}}{{{K}_{a}}.c}}\] \[=\sqrt{\frac{1\times {{10}^{-14}}}{1\times {{10}^{-5}}\times 0.001}}=\sqrt{\frac{1\times {{10}^{-14}}}{1\times {{10}^{-5}}\times 1\times {{10}^{-3}}}}\] \[=\sqrt{{{10}^{-\,6}}}={{10}^{-\,3}}\]
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