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JEE Main & Advanced Sample Paper JEE Main - Mock Test - 4

  • question_answer
    A certain player, say X, is known to win with probability \[0.3\] if the track is fast and \[0.4\] if the track is slow For Monday probability of a fast track is \[0.7\] and probability of a slow track is \[0.3\]. The probability that player X will win on Monday is                    

    A) \[0.22\]

    B) \[0.11\]                 

    C) \[0.33\]              

    D) \[0.44\]

    Correct Answer: C

    Solution :

    [c]   Let W: Player wins on Monday F: Track is fast S: Track is slow We are given that \[P(F)=0.7,\] \[P(S)=0.3,\] \[P(W/F)=0.3,\] \[P(W/F)=0.3,\]\[P(W/S)=0.4\] \[\therefore \,\,\,\,P(W)=P(W\cap F)+P(W\cap S)\] \[=P(F)\times P(W/F)+P(S)\times P(W/S)\] \[=0.7\times 0.3+0.3\times 0.4=0.33\]


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