A) \[C{{H}_{3}}C{{H}_{2}}CON{{H}_{2}}\]
B) \[C{{H}_{3}}C{{H}_{2}}COBr\]
C) \[C{{H}_{3}}C{{H}_{2}}N{{H}_{2}}\]
D) \[C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}N{{H}_{2}}\]
Correct Answer: C
Solution :
\[C{{H}_{3}}C{{H}_{2}}CN\xrightarrow{{{H}^{+}}/{{H}_{2}}O}C{{H}_{3}}C{{H}_{2}}COOH\xrightarrow[\Delta ]{N{{H}_{3}}}\]\[C{{H}_{3}}C{{H}_{2}}CON{{H}_{2}}\xrightarrow[NaOBr]{Hoffman\,\,bromied\,\,reaction}C{{H}_{3}}C{{H}_{2}}N{{H}_{2}}\]
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