A) \[\frac{3(V+v)}{\lambda }\]
B) \[\frac{3(V-v)}{\lambda }\]
C) \[\frac{(V+v)}{3\lambda }\]
D) \[\frac{(V-v)}{3\lambda }\]
Correct Answer: A
Solution :
[a] The relative velocity of sound waves with respect to the walls is\[V+v\]. Hence, the apparent frequency of the waves striking the surface of the wall is \[\frac{(V+v)}{\lambda }\] . The number of positive crests striking per second is the same as frequency. In three seconds, the number is \[[3\,(V+v)]/\lambda \].You need to login to perform this action.
You will be redirected in
3 sec