A) \[\frac{v}{2}\sqrt{1+2{{\cos }^{2}}\theta }\]
B) \[\frac{v}{2}\sqrt{1+{{\cos }^{2}}\theta }\]
C) \[\frac{v}{2}\sqrt{1+3{{\cos }^{2}}\theta }\]
D) \[v\cos \theta \]
Correct Answer: C
Solution :
[c] : From figure, Average velocity, \[{{v}_{av}}=\frac{\sqrt{{{H}^{2}}+({{R}^{2}}/4)}}{T/2}\] (i) Here,\[H=\frac{{{v}^{2}}{{\sin }^{2}}\theta }{2g};\] \[R=\frac{{{v}^{2}}\sin 2\theta }{g}\]and\[T=\frac{2v\sin \theta }{g}\] Putting these values in equation (i), we get, \[{{v}_{av}}=\frac{2}{2}\sqrt{1+3{{\cos }^{2}}\theta }\]You need to login to perform this action.
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