JEE Main & Advanced Sample Paper JEE Main - Mock Test - 7

  • question_answer
    A system is said to possess \[3N\] (where N particles are bound together to form a molecule) independent degree of freedom. Then the \[3N\] coordinates and components of motion are conveniently chosen as, translational (trans), rotational (rot) and vibrational (vib) motions. The total average energy contribution due to all the three modes for a linear miecule is

    A)  \[{{\left( \frac{3}{2}kT \right)}_{trans}}+{{(kT)}_{rot}}+{{[(3N-5)kT)}_{vib}}\]

    B)  \[{{\left( \frac{3}{2}kT \right)}_{rot}}+{{(kT)}_{vib}}+{{[(3N-5)kT]}_{trans}}\]

    C)  \[{{\left( \frac{3}{2}kT \right)}_{trams}}+{{\left( \frac{3}{2}kT \right)}_{rot}}+{{[(3N-6)kT]}_{vib}}\]

    D)  \[{{\left( \frac{3}{2}kT \right)}_{rot}}+{{\left( \frac{3}{2}kT \right)}_{vib}}+{{[(3N-6)kT]}_{trans}}\]

    Correct Answer: A

    Solution :

    [a] Relation (1) is for linear molecule and relation (3) is for non-linear molecules.


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