| Column I (Reaction) | Column II (Characteristics) | ||
| I. | \[2S{{O}_{2}}(g)+{{O}_{2}}(g)\rightleftharpoons 2S{{O}_{3}}(g)+46.9K.cal\] | P. | High P and T, shifts the equilibrium to right and or on adding inert gas at constant P and V, equilibrium is not affected |
| II. | \[PC{{l}_{5}}(g)\rightleftharpoons PC{{l}_{3}}(g)+C{{l}_{2}}(g)\] | Q. | Q. Decrease in V shifts the equilibrium to right and on adding inert gas at constant P shifts the equilibrium to left |
| III. | \[{{H}_{2}}O(s)\overset{at\,273\,K}{\mathop \rightleftharpoons }\,{{H}_{2}}O(1)\] | R. | Decrease in V shifts the equilibrium to left and on adding inert gas at constant P shifts the equilibrium to right |
| IV. | \[{{N}_{2}}(g)+{{O}_{2}}(g)\rightleftharpoons 2NO(g)\]\[-42.8kcal\] | S. | No effect on equilibrium of P or For on adding inert gas. But increase of T shifts the equilibrium to right |
A) I - R II - Q III - P IV - S
B) I - Q II - R III - S IV - P
C) I - Q II - R III - P IV - S
D) I - P II - S III - Q IV - R
Correct Answer: C
Solution :
| [c] Factual statement: |
| I. \[\Delta n=2-3=-1,\] |
| II. \[\Delta n=2-1=+1\] |
| III. Melting of ice |
| IV \[\Delta n=2-2=0\] |
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