A) \[2,7\]
B) \[5,8\]
C) \[3,6\]
D) \[2,6\]
Correct Answer: D
Solution :
\[{{T}_{4}}{{=}^{n}}{{C}_{3}}\,{{x}^{n-3}}{{\left( \frac{\alpha }{2x} \right)}^{3}}{{\Rightarrow }^{n}}{{C}_{3}}\,{{x}^{n-6}}{{\left( \frac{\alpha }{2} \right)}^{3}}=20\] If \[n=6,\] then \[^{6}{{C}_{3}}{{\left( \frac{\alpha }{2} \right)}^{3}}=20\Rightarrow \alpha =2\]
You need to login to perform this action.
You will be redirected in
3 sec
