A)
B) \[C{{H}_{3}}C{{H}_{2}}CH=CHC{{H}_{2}}C{{H}_{3}}\]
C) \[C{{H}_{3}}C{{H}_{2}}CH=CHC{{H}_{3}}\]
D) \[C{{H}_{3}}-\underset{C{{H}_{3}}}{\mathop{\underset{|}{\mathop{C}}\,}}\,=CHC{{H}_{3}}\]
Correct Answer: A
Solution :
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