A) \[W=\frac{{{W}_{1}}{{\rho }_{2}}+{{W}_{2}}{{\rho }_{1}}}{{{W}_{1}}+{{W}_{2}}}\]
B) \[W=\frac{{{W}_{1}}{{\rho }_{2}}-{{W}_{2}}{{\rho }_{1}}}{{{\rho }_{2}}-{{\rho }_{1}}}\]
C) \[W=\frac{{{W}_{1}}{{\rho }_{2}}+{{W}_{2}}{{\rho }_{1}}}{{{\rho }_{1}}+{{\rho }_{2}}}\]
D) \[W=\frac{{{W}_{1}}{{\rho }_{2}}-{{W}_{2}}{{\rho }_{1}}}{{{\rho }_{1}}-{{\rho }_{2}}}\]
Correct Answer: B
Solution :
[b] Loss in weight of liquid of density \[{{\rho }_{1}}\] is \[(W-{{W}_{1}})kg.\] Volume of liquid displaced, \[V=\frac{W-{{W}_{1}}}{{{\rho }_{1}}}\] Similarly, for 2nd liquid volume displaced \[V=\frac{W-{{W}_{1}}}{{{\rho }_{2}}}\] \[\therefore \,\,\,\,\,\,\frac{W-{{W}_{1}}}{{{\rho }_{1}}}=\frac{W-{{W}_{2}}}{{{\rho }_{2}}}\]You need to login to perform this action.
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