A) \[\frac{4P}{K{{T}_{0}}}\]
B) \[\frac{4P{{T}^{3}}}{KT_{0}^{4}}\]
C) \[\frac{2P{{T}^{3}}}{KT_{0}^{4}}\]
D) \[\frac{2P}{K{{T}_{0}}}\]
Correct Answer: B
Solution :
[b] \[dQ=Pdt\] \[{{C}_{p}}=\frac{P}{\left( \frac{dT}{dt} \right)}=\frac{P}{\frac{d}{dt}\left[ {{T}_{0}}\{1+K{{(t-{{t}_{0}}\}}^{1/4}} \right]}=\frac{4P{{T}^{3}}}{KT_{0}^{4}}\]You need to login to perform this action.
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