A) \[10\,\Omega \]
B) \[5\,\Omega \]
C) \[2\,\Omega \]
D) \[1\,\Omega \]
Correct Answer: B
Solution :
[b] \[\left( \frac{E}{\ell } \right)\times 20={{E}_{0}}\] \[\frac{\left[ E-\left( \frac{E}{10+x} \right)x \right]}{\ell }\times 30={{E}_{0}}\] \[1=\frac{3x}{10+x};\,\,\,x=5\Omega \]You need to login to perform this action.
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