A) \[K{{O}_{2}}\]
B) \[{{K}_{2}}{{O}_{2}}\]
C) \[{{K}_{2}}O\]
D) \[{{K}_{2}}C{{O}_{3}}\]
Correct Answer: A
Solution :
\[K{{O}_{2}}\xrightarrow{{}}{{K}^{+}}+O_{2}^{-}\] According to molecular orbital theory\[O_{2}^{-}\]will be paramagnetic and percentage of potassium \[=\frac{39}{39+32}\times 100\] \[=\frac{39}{71}\times 100\] = 55%
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