A) 940
B) 405
C) 90
D) None of these
Correct Answer: C
Solution :
\[P=P_{A}^{0}{{x}_{A}}+P_{B}^{0}{{x}_{B}}\] \[600=P_{A}^{0}\left( \frac{3}{3+2} \right)+P_{B}^{0}\left( \frac{2}{2+3} \right);3P_{A}^{0}+2P_{B}^{0}=3000\]\[630=P_{A}^{0}\left( \frac{4.5}{4.5+2+0.5} \right)+P_{B}^{0}\left( \frac{2}{4.5+2+0.5} \right)\] \[4.5P_{A}^{0}+2P_{B}^{0}=4410\] \[1.5P_{A}^{0}=1410;P_{A}^{0}=940\] and \[P_{B}^{0}=90\]You need to login to perform this action.
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