A) \[{{l}_{2}}+C{{u}^{2+}}\]
B) \[Cu{{l}_{2}}\]
C) \[{{l}_{2}}+Cu\]
D) \[C{{u}_{2}}{{l}_{2}}\]
Correct Answer: D
Solution :
\[{{I}^{-}}\] ions reduce \[C{{u}^{2+}}\] ions to \[C{{u}^{+}}\] ions. \[2CuS{{O}_{4}}\,+4KI\,\xrightarrow{\,}\,C{{u}_{2}}{{I}_{2}}+2{{K}_{2}}S{{O}_{4}}+{{I}_{2}}\]
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