Direction (Q. Nos. 88) For the existence of limit at \[x=a\] of \[y=f(x)\] it must be true that \[\underset{x\to \infty }{\mathop{\lim }}\,\,f(a+h)=\underset{h\to 0}{\mathop{\lim }}\,f(a+h)\]. Here, \[x=a\] is not the end point of the interval, \[\underset{x\to 0}{\mathop{\lim }}\,f(a-h)\] is called LHL and \[\underset{x\to 0}{\mathop{\lim }}\,f(a+h)\] is called RHL. |
A) 0
B) 1
C) - 1
D) not in existence
Correct Answer: A
Solution :
\[\,\underset{h\to 0}{\mathop{\lim }}\,\,\left[ \frac{\sin \,x}{\tan \,x} \right]=0\] as \[\sin \,x\,<\,\tan \,x\]You need to login to perform this action.
You will be redirected in
3 sec