2. Sample Papers
  3. JEE Main & Advanced

JEE Main & Advanced Sample Paper JEE Main Sample Paper-15

  • question_answer
    In a resonance tube water is filled so that height of air column is 0.1 m when it resonates in its fundamental mode. Now water is removed so that the height of air column becomes 0.35 m and it resonates with next higher frequency. Then end correction is

    A)  0.012                                   

    B)  0.025

    C)  0.05                                      

    D)  0.24

    Correct Answer: B

    Solution :

    End correction \[=\frac{{{L}_{2}}-3{{L}_{1}}}{2}=0.025\]


You need to login to perform this action.
You will be redirected in 3 sec spinner