JEE Main & Advanced Sample Paper JEE Main Sample Paper-15

  • question_answer
    A particle is executing SHM with period T and amplitude 13 cm, its equilibrium position being its velocity at a distance of \[x\] cm from O is 96 cm/s. Then T in seconds and \[x\] in cm may be

    A)
    \[T\] \[x\]
    \[5\pi /48\] 12

    B)
    \[T\] \[x\]
    \[\pi /4\] 6

    C)
    \[T\] \[x\]
    \[2\pi /15\] 8

    D)
    \[T\] \[x\]
    \[3\pi /20\] 10

    Correct Answer: A

    Solution :

    \[v=\frac{2\pi }{T}\sqrt{{{A}^{2}}-{{x}^{2}}}\]is satisfied by [A]


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