A) (3, 0)
B) (5, 0)
C) (0, 0)
D) (4, 0)
Correct Answer: C
Solution :
The equation of tangent at P \[(5\cos \theta ,4\sin \theta )\]is \[\frac{x}{5}\cos \theta +\frac{y}{4}\sin \theta =1\].Point Q is \[(0,4\,\cos ec\theta )\]and R is \[(4\,\cos ec\theta ,0)\]equation of circle is \[x(x-4\,\cos ec\theta )+y(y-4\cos ec\,\theta )=0\] i.e.\[{{x}^{2}}+{{y}^{2}}-4(x+y)\cos ec\theta =0\]You need to login to perform this action.
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