A) \[{{x}^{2}}+{{y}^{2}}=8\]
B) \[{{x}^{2}}+{{y}^{2}}=34\]
C) \[{{x}^{2}}+{{y}^{2}}=64\]
D) \[{{x}^{2}}+{{y}^{2}}=81\]
Correct Answer: D
Solution :
Normal to ellipse at P is \[\frac{5x}{\cos \theta }-\frac{4y}{\sin \theta }=9\]..(i) equation of normal to circle at Q is \[y=x\tan \theta \] ..(ii) eliminating\['\theta '\]from (i) and (ii) we get \[{{x}^{2}}+{{y}^{2}}=81\]You need to login to perform this action.
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