A) \[H/4\]
B) \[~2H\]
C) \[~4H\]
D) \[~SH\]
Correct Answer: C
Solution :
In series,\[{{R}_{s}}=2R,\] where R is the thermal resistance of one cylinder \[H=\frac{{{T}_{1}}-{{T}_{2}}}{{{R}_{s}}}=\frac{{{T}_{1}}-{{T}_{2}}}{2R}.\] In parallel, \[{{R}_{p}}=R/2.\] \[\therefore \] \[{{H}_{p}}=\frac{{{T}_{1}}-{{T}_{2}}}{{{R}_{p}}}=\frac{{{T}_{1}}-{{T}_{2}}}{R/2}=4H\]You need to login to perform this action.
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