JEE Main & Advanced Sample Paper JEE Main Sample Paper-17

  • question_answer
    Aniline is weaker base than ethyl amine. This is due to

    A)  \[-\text{I}\]effect of \[\text{N}{{\text{H}}_{\text{2}}}\]in aniline

    B) \[~-\text{R}\] effect of \[\text{N}{{\text{H}}_{\text{2}}}\]in aniline

    C)  \[\text{+}\,\text{I}\]effect of \[\text{N}{{\text{H}}_{2}}\]in aniline

    D) \[+R\]effect of \[\text{N}{{\text{H}}_{\text{2}}}\]in aniline

    Correct Answer: D

    Solution :

     Lone pair on \[\text{N}{{\text{H}}_{2}}\]group is involved in resonance with the ring in aniline.


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