A) \[500\text{ }K\]
B) \[1500\text{ }K\]
C) \[1500{}^\circ C\]
D) \[135{}^\circ C\]
Correct Answer: B
Solution :
\[{{d}_{1}}=\frac{M}{V}=\frac{12}{4\times {{10}^{3}}}=3\times {{10}^{-3}}g\,c{{m}^{-3}}\] \[\frac{{{d}_{1}}}{{{d}_{2}}}=\frac{{{T}_{2}}}{{{T}_{1}}}\Rightarrow \frac{3\times {{10}^{-3}}}{6\times {{10}^{-4}}}=\frac{{{T}_{2}}}{300\,K}\] \[\Rightarrow \] \[{{T}_{2}}=5\times 300=1500\,K\]
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