JEE Main & Advanced Sample Paper JEE Main Sample Paper-18

  • question_answer
    The ratio between the squares of root mean square velocity of\[{{H}_{2}}\]at 50 K and that of\[{{N}_{2}}\]at 800 K is

    A)  \[4\]                                    

    B)  \[2\]

    C)  \[\frac{7}{8}\]                                  

    D)  \[\frac{1}{4}\]

    Correct Answer: C

    Solution :

     \[\frac{u_{{{H}_{2}}}^{2}}{u_{{{N}_{2}}}^{2}}=\frac{\frac{3R{{T}_{1}}}{{{M}_{1}}}}{\frac{3R{{T}_{2}}}{{{M}_{2}}}}=\frac{{{T}_{1}}}{{{T}_{2}}}\times \frac{{{M}_{1}}}{{{M}_{2}}}=\frac{50}{800}\times \frac{28}{2}=\frac{1400}{1600}=\frac{7}{8}.\]


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