JEE Main & Advanced
Sample Paper
JEE Main Sample Paper-19
question_answer
\[\lambda \]for which \[\frac{x-2}{-3}=\frac{y-4}{7}=\frac{z-8}{\lambda }\] and\[\frac{x-1}{\lambda }=\frac{y-2}{-3}=\frac{z-3}{6}\] are perpendicular equals
A)\[5\]
B)\[6\]
C)\[7\]
D)\[8\]
Correct Answer:
C
Solution :
For perpendicularity\[-3\lambda -21+6\lambda =0\Rightarrow \lambda =7\].