JEE Main & Advanced Sample Paper JEE Main Sample Paper-19

  • question_answer If \[2\sec 2\alpha =\tan \beta +\cot \beta \] then one of the values of\[(\alpha +\beta )=\]

    A) \[\pi \]                                 

    B) \[\frac{\pi }{2}\]

    C) \[\frac{\pi }{4}\]                                              

    D)  None

    Correct Answer: C

    Solution :

    \[\frac{2}{\cos 2\alpha }=\frac{{{\tan }^{2}}\beta +1}{\tan \beta }=\frac{1}{\sin \beta \cos \beta }\] \[\Rightarrow \]\[\sin 2\beta =\cos 2\alpha =\sin (90-2\alpha )\Rightarrow \alpha +\beta =\frac{\pi }{4}\]

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