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JEE Main & Advanced Sample Paper JEE Main Sample Paper-19

  • question_answer
    The eccentricity of the ellipse represented by\[25{{x}^{2}}+16{{y}^{2}}-150x-175=0\]is

    A) \[\frac{2}{5}\]                                   

    B) \[\frac{3}{5}\]

    C) \[\frac{4}{5}\]                                   

    D) \[\frac{1}{5}\]

    Correct Answer: B

    Solution :

     The ellipse \[\Rightarrow \]   \[\frac{{{(x-3)}^{2}}}{16}+\frac{{{y}^{2}}}{25}=1\]      \[\therefore \,\,\frac{16}{25}=1-{{e}^{2}}\Rightarrow e=\frac{3}{5}\]


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