A) \[190\,k\Omega \]
B) \[90\,k\Omega \]
C) \[290\,k\Omega \]
D) \[390\,k\Omega \]
Correct Answer: C
Solution :
Given \[(10\,k\Omega )I=4V\] OR\[10\,k\Omega \]. \[\frac{120V}{X+10k\Omega }=4V\] OR \[300k\Omega =X+10k\Omega ;\] \[X=2901\,k\Omega \]You need to login to perform this action.
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