A) \[I=p+mgt\]
B) \[\tau =(m{{v}^{2}}/2)+Fr\]
C) \[mvr=I\omega +Fr\]
D) \[\frac{L}{R}=RC+t\frac{r}{(1/\sqrt{{{\mu }_{0}}{{\in }_{0}}})}\]
Correct Answer: C
Solution :
mvr and \[I\omega \] has same dimensions \[[M{{L}^{2}}{{T}^{-1}}]\], while Fr has dimensions \[[M{{L}^{2}}{{T}^{-2}}].\]
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