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JEE Main & Advanced Sample Paper JEE Main Sample Paper-1

  • question_answer
    A tuning fork of frequency 512 Hz is vibrated with a sonometer wire and 6 beats/s are heard. The beat frequency reduces, if the tension in the string is slightly increased. The original frequency of vibration of the string is

    A)  506 Hz                                 

    B)  512 Hz

    C)  518 Hz                                 

    D)  524 Hz

    Correct Answer: A

    Solution :

    Let original frequency of sonometer wire is f Hz, then f = 512 ± 6 = 518 or 506 Hz. When tension in the string is increased, frequency of string increases, while beat frequency is decreasing. \[512=f+{{f}_{b}}\]or \[f-{{f}_{b}}\]where \[{{f}_{b}}\] is beat frequency. If f is increasing then beat frequency has to decrease from 1st expression while it will increase in, accordance with 2nd expression. For given situation 1st equation is valid, so \[f=512-6=506Hz.\]


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