JEE Main & Advanced Sample Paper JEE Main Sample Paper-1

  • question_answer
    Direction: Question No. 30 are based on the following paragraph. A wire of length L, mass m and carrying a current is suspended from point O as shown. An infinitely long wire carrying the same current I is at a distance L below the lower end of the wire. Given, I = 2A, L= 1m and m = 0.1 kg (ln 2 = 0.693) We want to keep the suspended wire stationary by placing a third infinitely long wire carrying an upward current. Then this wire should be placed.

    A)  to the left of suspended wire

    B)  to the right of suspended wire

    C)  We can't of suspended wire stationary be placing a third wire to the right or to the left of it

    D)  we can keep it either to the right or to the left. It will depend on the magnitude of the current in the third wire

    Correct Answer: A

    Solution :

    Net torque about O should be zero. Magnetic field on the suspended wire due to already placed wire is perpendicular to paper outward. Hence, magnetic field on suspended wire due to new wire should be perpendicular to paper inwards.


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