A) \[{{A}_{3}}{{B}_{2}}{{O}_{4}}\]
B) \[{{A}_{2}}{{B}_{2}}{{O}_{4}}\]
C) \[A{{B}_{2}}{{O}_{5}}\]
D) \[A{{B}_{2}}{{O}_{4}}\]
Correct Answer: D
Solution :
Let number of oxides = x Number of octahedral void = x Number of tetrahedral void = 2 x Number of \[{{A}^{2+}}\]ion \[=\frac{1}{8}.2x=\frac{x}{4}\] Number of \[{{B}^{3+}}\] ion \[=\frac{x}{2}\] \[\begin{matrix} {{A}^{2+}}: & {{B}^{3+}}: & {{O}^{2-}} \\ \frac{x}{4}: & \frac{x}{2}: & x \\ 1 & 2 & 4 \\ \end{matrix}\] Hence, formula of oxide is \[A{{B}_{2}}{{O}_{4}}.\]You need to login to perform this action.
You will be redirected in
3 sec