A) 100
B) - 100
C) 50
D) - 50
Correct Answer: D
Solution :
\[\alpha +\beta \,=\frac{-q}{p};\,\,\alpha \beta \,=\frac{r}{p}\] Also \[2q=p+r\] \[\therefore \,\frac{2q}{p}=1+\frac{r}{p}\] \[-2(\alpha +\beta )\,=\alpha \beta \,=1+99=100\] \[\Rightarrow \,(\alpha +\beta )\,=-50\]You need to login to perform this action.
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