A) \[{{K}_{2}}C{{r}_{2}}{{O}_{7}}\backslash {{H}_{2}}S{{O}_{2}}\] dil. NaOH
B) \[LiAl{{H}_{4}}\] di LHCl
C) \[Zn-Hg,\text{ }HCI\] Cone. \[{{H}_{2}}S{{O}_{4}}\]
D) \[NaB{{H}_{4}},C{{H}_{3}}OH\] Cone. \[{{H}_{2}}S{{O}_{4}}\]
Correct Answer: D
Solution :
\[C{{H}_{3}}\,-\overset{\begin{smallmatrix} OH \\ \,\,\,\,\,\,\,| \end{smallmatrix}}{\mathop{C}}\,-C{{H}_{3}}\xrightarrow[C{{H}_{4}}OH]{NaB{{H}_{4}}}\,C{{H}_{3}}-\overset{\begin{smallmatrix} OH \\ \,\,\,\,\,\,\,| \end{smallmatrix}}{\mathop{C}}\,-C{{H}_{3}}\xrightarrow[Dehydration]{Conc.\,{{H}_{2}}S{{O}_{4}}}\]\[C{{H}_{3}}-CH=C{{H}_{2}}\]You need to login to perform this action.
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