A) 18 gm
B) 4 gm
C) 36 gm
D) 16 gm
Correct Answer: C
Solution :
\[\frac{{{W}_{1}}}{{{E}_{1}}}\,=\frac{{{W}_{2}}}{{{E}_{2}}};\,\frac{4}{12}\,=\frac{{{W}_{Ag}}}{108};\,\,{{W}_{Ag}}\,=36\]You need to login to perform this action.
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