A) 8
B) \[8\sqrt{2}\]
C) 4
D) \[4\sqrt{2}\]
Correct Answer: B
Solution :
\[N:y+tx=2t+{{t}^{3}};\] slope of the normal is - t Hence \[-t=1\Rightarrow \,t=-1\] \[\Rightarrow \] coordinates of P are (1, -2) Hence parameter at Q, \[{{t}_{2}}=-{{t}_{1}}-2/{{t}_{1}}=1+2=3\] \[\therefore \] coordinates at Q are (9, 6) \[\therefore \] \[l(PQ)\,=\sqrt{64+64}\,=8\sqrt{2}\]You need to login to perform this action.
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