A) 2
B) 3
C) 4
D) 5
Correct Answer: B
Solution :
Clearly \[{{m}_{MA}}\,\times {{m}_{BC}}=-1\] \[\Rightarrow \,\,\frac{k-2}{h-1}\,\times 1=-1\] \[\Rightarrow \,k-2=1-h\] \[\therefore \] Locus of \[H(h,k)\] is \[x+y=3\]You need to login to perform this action.
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