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JEE Main & Advanced Sample Paper JEE Main Sample Paper-23

  • question_answer
    X-rays are diffracted from a crystal of lattice plane spacing \[2\overset{0}{\mathop{A}}\,\]. The maximum wavelength that can be diffracted is:

    A) \[1\overset{\text{o}}{\mathop{A}}\,\]

    B) \[2\overset{\text{o}}{\mathop{A}}\,\]

    C) \[2.5\overset{\text{o}}{\mathop{A}}\,\]

    D) \[4\overset{\text{o}}{\mathop{A}}\,\]

    Correct Answer: D

    Solution :

    Using Bragg's formula \[2d\sin \theta \,=\lambda \] Given, d = 2A For the maximum wavelength sin = 1 \[{{\lambda }_{\min }}\,=2d=2\times 2\overset{\text{o}}{\mathop{\text{A}}}\,=4\overset{\text{o}}{\mathop{\text{A}}}\,\]


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