JEE Main & Advanced Sample Paper JEE Main Sample Paper-24

  • question_answer
    Two blocks of equal masses m are released from the top of a smooth fixed wedge as shown in the figure. The acceleration of the centre of mass of the two blocks is :

    A)  g                                 

    B)  \[\frac{g}{2}\]

    C)  \[\frac{3g}{4}\]                        

    D)  \[\frac{g}{\sqrt{2}}\]

    Correct Answer: B

    Solution :

    The acceleration of the centre of mass of the block \[=\left| \frac{m{{{\vec{a}}}_{1}}+m{{{\vec{a}}}_{2}}}{m+m} \right|\,=\frac{1}{2}\,\sqrt{a_{1}^{2}\,+a_{2}^{2}}\] \[=\frac{g}{2}\,\sqrt{{{(\sin \,\angle \,ABC)}^{2}}\,+{{(\sin \,\angle ACB)}^{2}}}\] \[=\frac{g}{2}\,\sqrt{{{\sin }^{2}}\,{{30}^{0}}\,+{{\sin }^{2}}\,{{60}^{0}}}\] \[=\frac{g}{2}\,\sqrt{{{(0.5)}^{2}}\,+{{(0.866)}^{2}}}=\frac{g}{2}\]


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