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JEE Main & Advanced Sample Paper JEE Main Sample Paper-25

  • question_answer
    The entropy change can be calculated by using the expression \[\Delta S=\frac{{{q}_{rev}}}{T}\] .When water freezes in a glass beaker, choose the correct statement amongst the following:

    A)  \[\Delta S\] (system) decreases but \[\Delta S\] (surroundings) remains the same.

    B)  \[\Delta S\] (system) increases but \[\Delta S\] (surroundings) decreases.

    C)  \[\Delta S\] (system) decreases but \[\Delta S\] (surroundings) increases.

    D)  \[\Delta S\] (system) decreases and \[\Delta S\] (surroundings) also decreases.

    Correct Answer: C

    Solution :

    Freezing is exothermic process. The heat released increases the entropy of surrounding.


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