A) 20 m
B) 30 m
C) 40 m
D) 60 m
Correct Answer: A
Solution :
Let height of tree = x In \[\Delta ABC,\] \[\frac{h}{x}=\tan {{60}^{0}}\Rightarrow \,h=\sqrt{3}x\] In \[\Delta ABD,\] \[\frac{h}{x+40}\tan {{30}^{0}}\] \[\Rightarrow \,\,\sqrt{3}h\,=x+40\] \[\therefore \] From (1) and (2), we get x = 20m.You need to login to perform this action.
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