A) v
B) \[\sqrt{3v}\]
C) \[\frac{2}{\sqrt{3}}v\]
D) \[\frac{v}{\sqrt{3}}\]
Correct Answer: C
Solution :
In x-direction \[m{{u}_{1}}+0=0+m{{v}_{x}}\]Or \[mv=m{{v}_{x}}\]\[{{v}_{x}}=v\] In y-direction \[0+0\,=m\left( \frac{v}{\sqrt{3}} \right)\,-m{{v}_{y}},\,\,or\,\,{{v}_{y}}=\frac{v}{\sqrt{3}}\] Velocity of second mass after collision, \[v'=\,\sqrt{{{\left( \frac{v}{\sqrt{3}} \right)}^{2}}+{{v}^{2}}}\,=\sqrt{\frac{4}{3}{{v}^{2}}}\]\[v'\,=\frac{2}{\sqrt{3}}v\]You need to login to perform this action.
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