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JEE Main & Advanced Sample Paper JEE Main Sample Paper-26

  • question_answer
    The rate constant of a first order reaction is \[4\times {{10}^{-3}}{{\sec }^{-1}}\] At a reactant concentration of \[0.02\] M. the rate of reaction would be :

    A)  \[8\times {{10}^{-5}}\] M \[{{\sec }^{-1}}\]   

    B)  \[4\times {{10}^{-3}}\] M \[{{\sec }^{-1}}\]

    C)  \[2\times {{10}^{-1}}\]M \[{{\sec }^{-1}}\]     

    D)  \[4\times {{10}^{-1}}\]M \[{{\sec }^{-1}}\] 

    Correct Answer: A

    Solution :

    \[R=K[A]\]\[R=4\times {{10}^{-3}}\,\times 0.02=8\,\times {{10}^{-5}}M\,{{\sec }^{-1}}\]


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