A) P(A) + P(B) = 1
B) \[P(A'\cap B)=0\]
C) A and B are equally likely
D) \[P(A'\cup B')=0\]
Correct Answer: A
Solution :
\[P(A\cup B)\,=P(A\cap B)\] \[\Rightarrow \,\,\,P(A)\,=P(B)\,=P(A\cup B)\,=P(A\cap B)\]You need to login to perform this action.
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